Elastic FE models
Stress path
Concrete principal stress
Elastic Linear FE
Nonlinear FE (Muttoni etal, 2007)
STM models
(source: Muttoni etal, 2007)
fig.3
Reinforce bars arrangement
fig.4
Kontur tulangan perlu arah datar (H)
Kontur tulangan perlu arah tegak (V)
Perbedaan hasil ditampilkan dengan bar chart berikut,
Pola retak dan kapasitas beban ultimit pada beberapa jenis model STM dan konfigurasi tulangan hasil penelitian Maxwell, B.S. (1996) dgn scaled down 5.5
Terlihat konfigurasi tulangan orthogonal dgn kombinasi diagonal menghasilkan kapasitas beban ultimit lebih besar dibandingkan konfigurasi tulangan lainnya. Semua model mencapai beban terfaktor yg direncanakan sebesar 22Kips (Maxwell, 1996)
calculation pads,
' Horizontal bars Reinforcement
As1=Avg(3.599,1.735,0.719,0,0)*500*0.9/0.75= 726.36
reff1a=2*0.25*Pi*25^2= 981.75
reff1b=2*0.25*Pi*20^2= 628.32
As2=Avg(2.558,0.702,1.267,1.124,0.878)*500*0.9/0.75= 783.48
reff2a=2*0.25*Pi*25^2= 981.75
reff2b=3*0.25*Pi*20^2= 942.48
As3=Avg(3.833,2.095,1.359)*(2338-2000)*0.9/0.75= 985.20
reff3a=2*0.25*Pi*25^2= 981.75
As3=Avg(3.833,2.095,1.359,0.698)*(2675-2000)*0.9/0.75= 1616.96
reff3b=7*0.25*Pi*16^2= 1407.43
As4=Avg(2.775,0.0386,0.0481,0.031,0.005,0.073,0)*(2000-500)*0.9/0.75= 763.89
reff4=6*0.25*Pi*12^2= 678.58
As5=Avg(3.832,0.553,0.153,0.102,0,0.143,0)*(2000-500)*0.9/0.75= 1229.91
reff5=6*0.25*Pi*12^2= 678.58
' Vertical bars Reinforcement
As1=Avg(3.343,1.716,1.165,0.700)*(2625-2000)*0.9/0.75= 1298.25
reff1a=2*0.25*Pi*25^2+2*0.25*Pi*12^2= 1207.94
As1=Avg(3.343,1.716,1.165,0.700,0.456)*(2938-2000)*0.9/0.75= 1661.39
reff1b=7*0.25*Pi*16^2= 1407.43
As2=Avg(0,0.640,0.097,0.153,0.148,0.571,3.343)*(2000-500)*0.9/0.75= 1273.37
reff2a=7*0.25*Pi*12^2= 791.68
reff2b=6*0.25*Pi*12^2= 678.58
As3=Avg(0.049,0.021,0.027,0.025,0.029,0.027,0.027,0.0258,0.027,0.022,0.029,0.018,0.04,0.027,0.06,0.071,0.121,0.258,0.492,2.6180)*(7000-2000)*0.9/0.75= 1204.14
reff3a=16*0.25*Pi*12^2= 1809.56
reff3b= 0.00
' Minimum bars reinforcement
A_smin=0.002*1000*400-50= 750.00
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